a+b=7, ab=18
find a–b
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Answer:
a+b = 7
a = 7-b
Substitute a in ab = 18
(7-b)(b) = 18
7b+b²-18 = 0
b²+7b-18 = 0
b²+9b-2b-18 = 0
b(b+9)-2(b+9) = 0
(b-2)(b+9) = 0
Either b-2 = 0 or b+9 = 0
b = 2 or -9
We will consider positive values,
So if b= 2 , a= 7-2 = 5
a-b = 5-2 = 3
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