Question

a+b=7and ab=6 then find the value of a²-b²​

Answer 1

Answer:

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Step-by-step explanation:

Given, a+b=7  and ab=6  

Now,

$(a+b)^{2}$ = $a^{2}$ + $b^{2}$ + 2ab

$7^{2}$ = $a^{2}$ + $b^{2}$ + 2*6

49-12 = $a^{2}$ + $b^{2}$

$a^{2}$ + $b^{2}$ = 37.

Now,

$(a-b)^{2}$ = $a^{2}$ + $b^{2}$ - 2*6

$(a-b)^{2}$ = 37-12

$(a-b)^{2}$ = 25

a - b = $sqrt{25}$

a-b = + or - 5

a²-b²​ = (a+b)(a-b)

a²-b² = 7 * 5

a²-b² = + or - 35