Question

∠a+∠b=85 and ∠b+∠c=130 fin
d value of ∠b and∠c​

Answer 1

$\huge{\mathbb{\red{ANSWER:-}}}$

Given :-

$\sf{\angle A + \angle B = 85}$

$\sf{\angle B + \angle C = 130}$

To Find Out :-

$\sf{value \: of \: \angle b \: and \: \angle c}$

Using Identity :-

$\sf{Sum \: of \: all \: three \: angles \: of \: triangle}$

$\sf{is \: 180}$

$\sf{means , \: \angle A + \angle B + \angle C=180}$

Solution :-

$\sf{As \: we \: have \: given-}$

$\sf{\angle A + \angle B = 85}$ --(1)

$\sf{\angle B + \angle C = 130}$ --(2)

$\sf{From \: eq.(1) + eq.(2)-}$

$\sf{\angle A + 2\angle B + \angle C = 215}$

$\sf{180 + \angle B = 215}$

$\sf{\angle B = 35}$

$\sf{then}$

$\sf{\angle C =130 - 35}$

$\sf{\angle C = 95}$

$\sf{\angle A = 85 - 35}$

$\sf{\angle A = 50}$

Result :-

$\sf{\angle B = 35}$

$\sf{\angle C = 95}$

Answer 2

Answer:

$</p><p>{\mathbb{\pink{ANSWER:-}}}$

Given :-

$\sf{\angle A + \angle B = 85}$

$\sf{\angle B + \angle C = 130}$

To Find Out :-

$\sf{value \: of \: \angle b \: and \: \angle c}$

Using Identity :-

$\sf{Sum \: of \: all \: three \: angles \: of \: triangle}$

$\sf{is \: 180}$

$\sf{means , \: \angle A + \angle B + \angle C=180}$

Solution :-

$\sf{As \: we \: have \: given-}$

$\sf{\angle A + \angle B = 85}$

$\sf{\angle B + \angle C = 130}$

$\sf{From \: eq.(1) + eq.(2)-}$

$\sf{\angle A + 2\angle B + \angle C = 215}$

$\sf{180 + \angle B = 215}$

$\sf{\angle B = 35}$

$\sf{then}$

$\sf{\angle C =130 - 35}$

$\sf{\angle C = 95}$

$\sf{\angle A = 85 - 35}$

$\sf{\angle A = 50}$

Result :-

$\sf{\angle B = 35}$

$\sf{\angle C = 95}$

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