Question

a+b=86,b+c=73,a+c=15then what for a, b, c, each? ​

Answer 1

Step-by-step explanation:

a+b-(b+c) = 86-73

» a-c = 13

Given a+c = 15

» a+c+(a-c) = 15+13

» 2a = 28

» a = 14

substitute this in the equation a+c = 15

» c = 15-a =15-14=1

» c = 1

Given b+c= 73

» b= 73-c

» b = 72

Answer 2

Answer:

a+b = 86 ...........(i)

b+c = 73 .............(ii)

a+c = 15 ...............(iii)

subtract by eq. (i) and eq. (ii)

a+b -(b+c) = 86 -73

a+b-b-c = 13

a-c = 13 .............(iv)

subtract by eq. (ii) and eq. (iii)

b+c -(a+c) = 73-15

b+c-a-c = 58

b-a = 58 ...........(v)

adding eq. (i) and (v)

a+b = 86

-a+b = 58

_________

2b = 144

b = 72

put b = 72 in eq. (i)

a+b = 86

a+72 = 86

a = 86-72

a = 14

put a = 14 in eq. (iii)

a+c = 15

14+c = 15

c = 15-14

c = 1

Hence, the value of a,b and c is 14,72 and 1.