Math, asked by devik, 1 year ago

A+B=90 secA =5/3, find the value of cosecB

Answers

Answered by Ayusha765
61
secA=5/3
=>cosA=3/5
=>sin(90-A)=3/5
=>sinB=3/5 (since A+B=90)
=>cosecB=5/3
Answered by mysticd
4

Answer:

Value of cosecB = SecA = 5/3

Explanation:

Given ,

A+B = 90°

=> A = 90°-B ----(1)

and

secA = \frac{5}{3}----(2)

\implies sec(90-B) = \frac{5}{3}

/* From (1) */

cosecB = \frac{5}{3}

/* We know that,

Sec(90-B) = cosecB */

Therefore,

Value of cosecB = SecA = 5/3

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