A+B=90 secA =5/3, find the value of cosecB
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Answered by
61
secA=5/3
=>cosA=3/5
=>sin(90-A)=3/5
=>sinB=3/5 (since A+B=90)
=>cosecB=5/3
=>cosA=3/5
=>sin(90-A)=3/5
=>sinB=3/5 (since A+B=90)
=>cosecB=5/3
Answered by
4
Answer:
Value of cosecB = SecA = 5/3
Explanation:
Given ,
A+B = 90°
=> A = 90°-B ----(1)
and
----(2)
/* From (1) */
/* We know that,
Sec(90-B) = cosecB */
Therefore,
Value of cosecB = SecA = 5/3
•••
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