Question

A+B=90° sinA=a, sinB=b then prove that tanA=a/b

Answer 1

$given \: \: A + B = 90 \: \: \\ \sin(A) = a - - - (1)\\ \\ \sin(B) = b \\ \sin(90 - A) = b \\ \cos(A) = b - - - (2) \\ \\ \frac{(1)}{(2)} \: \: gives \\ \tan(A) = \frac{a}{b}$