Math, asked by eswarisenthil8pdge3z, 1 year ago

A+B=90° then cosAsinB +sinAcosB is equal to

Answers

Answered by ask2109

4

sinacosb + cosasinb=sin(a+b)
so sin 90=1

eswarisenthil8pdge3z: Hey ur answer is correct but i want to how sin90

ask2109: its an identity

eswarisenthil8pdge3z: Ok

ask2109: ya

Answered by chouhanharshvardhans

1

A+B=90 (given)

sinA.cosB+sinB.cosA

=sin(A+B)cos(A+B)

=sin90×cos90 [sin90=1 cos90=0]

=1×0

=0

Therefore the answer is 0.

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