A+B=90° then cosAsinB +sinAcosB is equal to
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4
sinacosb + cosasinb=sin(a+b)
so sin 90=1
so sin 90=1
eswarisenthil8pdge3z:
Hey ur answer is correct but i want to how sin90
its an identity
Ok
ya
Answered by
1
A+B=90 (given)
sinA.cosB+sinB.cosA
=sin(A+B)cos(A+B)
=sin90×cos90 [sin90=1 cos90=0]
=1×0
=0
Therefore the answer is 0.
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