Question

(a+b)(a+b)(a+b)+(a-b)(a-b)(a-b))

Answer 1

=(a+b)(a+b)(a+b)+(a-b)(a-b)(a-b)

$= {(a + b)}^{3} + {(a - b)}^{3} \\ = {a}^{3} + {b}^{3} + 3ab(a + b) + {a}^{3} - {b}^{3} - 3ab(a - b) \\ ={a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {a}^{3} - {b}^{3} - 3 {a}^{2}b + 3a {b}^{2} \\ = 2 {a}^{3} + 6 {ab}^{2} \\ = 2a( {a}^{2} + 3 {b}^{2} )$

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Answer 2

Answer:

Step-by-step explanation:

(a+b)(a+b)(a+b)+(a-b)(a-b)(a-b)

(a+b)^3+(a-b)^3

((a+b)+(a-b))^3