a+b=a×b=a÷b
find the values of a and b
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Answer:
which means a and b are not equal to 1 because everything multiplied by one equals to itself while a number added by 1 doesn't)
ab=a/b
ab^{2} =aab
2
=a
\begin{gathered}ab^{2}=a \\ab^{2}-a=0\\a (b^{2}-1 )=0\\\end{gathered}
ab
2
=a
ab
2
−a=0
a(b
2
−1)=0
a=0 or b= ± 1
since b≠1 ; b= -1
a=0 --> a+b=ab; therefore b=0 for this function
a+b=a/b
1. For (a,b) = (0,0)
0+0≠0/0 because 0/0 is undefined, therefore it is not true
2. For b=-1
\begin{gathered}a+b=\frac{a}{b}\\a-1=\frac{a}{-1} \\a-1=-a\\2a=1\\a=\frac{1}{2}\end{gathered}
a+b=
b
a
a−1=
−1
a
a−1=−a
2a=1
a=
2
1
therefore (a,b) = (1/2,-1)
apply to a+b=ab
1/2 - 1 = 1/2 x -1 = -1/2 (the equation if correct)
a-b= 1/2-1 = -1/2
Step-by-step explanation:
Thanks!
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