Question

(a+b) (a-b) (a²+b²)?​

Answer 1

Answer:

= a(a-b)-b(a-b) [Addition Distributive Law]

=a²-ab-ba+b² [Addition Distributive Law]

=a²-ab-ab+b² [Multiplication Commutative Law]

=a²-2ab+b²

So, (a-b)²= a²-2ab+b²

Again we know

(a+b)²= (a+b)(a+b)

= a(a+b)+b(a+b) [Addition Distributive Law]

=a²+ab+ba+b² [Addition Distributive Law]

=a²+ab+ab+b² [Multiplication Commutative Law]

=a²+2ab+b²

So, (a+b)²= a²+2ab+b²

Now, (a+b)² - 4ab= a²+2ab+b² -4ab= a²+2ab-4ab+b²= a²-2ab+b² = (a-b)²

So, (a-b)² = (a+b)² - 4ab

Finally we can say

(a-b)²= a²-2ab+b²

and also “hope this helps!!”

(a-b)² = (a+b)² - 4ab

Step-by-step explanation:

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