(a+b)(a-b)(a²+b²)
multiply using identies
Answers
Answer:
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Step-by-step explanation:
a² - b² = (a+b)(a-b)
Here a and b are the real numbers.
(a+b)(a-b)
=a(a-b)+b(a-b) [Addition Distributive Law]
=a²-ab+ba-b² [Addition Distributive Law]
=a²-ab+ab-b² [Multiplication Commutative Law]
=a²+0-b² [Addition Law of Identity]
=a²-b² [Addition Law of Identity]
so, a² - b² = (a+b)(a-b)
Addition Distributive Law: (A + B) X = (A X) + (B X)
Multiplication Commutative Law: XY=YX
Addition Law of Identity: A+(-A)=0 and A+0=A
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Srinivas
Answered 2 years ago
Its an identity
The power is represented by ^
a^2-b^2=(a+b)×(a-b)
Let's prove it…
a(a-b)+b(a-b)
a^2-ab+ba-b^2
-ab and +ab get cancelled
a^2-b^2
so…,
a^2-b^2=(a+b)(a-b)
Hope this answer helps you….
Thank you..!