Math, asked by ansh100711, 8 months ago

(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0​

Answers

Answered by parzival3620
1
(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0
(a^2-b^2)+(b^2-c^2)+(c^2-a^2)=0
a^2-b^2+b^2-c^2+c^2-a^2=0
0=0
I hope this helps
Please mark me as the brainiest
Similar questions