(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0
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Answer:
answer is 0
Step-by-step explanation:
a(a+b)-b(a+b)+b(b+c)-c(b+c)+c(c+a)-a(c+a)
a^2+ab-ab-b^2+b^2+bc-cb-c^2+c^2+ac-ac-a^2
then cut + to -
this type
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