Math, asked by vandeshpatil160, 4 months ago

(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0​

Answers

Answered by s115499ailma02691
1

Answer:

answer is 0

Step-by-step explanation:

a(a+b)-b(a+b)+b(b+c)-c(b+c)+c(c+a)-a(c+a)

a^2+ab-ab-b^2+b^2+bc-cb-c^2+c^2+ac-ac-a^2

then cut + to -

this type

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