Math, asked by vandeshpatil160, 5 months ago

(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0​

Answers

Answered by nandinibalaji47
3

(a-b)(a+b) = a² - b²

(b-c)(b+c) = b² - c²

(c-a)(c+a) = c² - a²

a² - b² + b² - c ² + c ² - a²

= 0

Hope the answer helps u !!

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Answered by namratakargutkar78
1

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