Question

(a+b)(a-b) +(b-c) (b+c)+(c-a) (c+a)=0​

Answer 1

Answer:

yes it's correct..

BTW

what do U want..

I don't get it

Answer 2

Step-by-step explanation:

l. h. s. = (a+b)(a-b) +(b-c)(b+c)+(c-a) (c+a)

= a^2-b^2 + b^2-c^2 +c^2-a^2

=0 == r. h. s.

l. h. s. == r. h. s.

I hope it will help