Question

(a - b)(a + b) + (b - c)(b + c)+(c - a)(c + a) = 0​

Answer 1

Answer:

a²-b²+b²-c²+c²-a²

a²-a2+b²-b²+c²-c²

=0

Answer 2

Step-by-step explanation:

(a- b)(a + b) + (b - c)(b + c)+(c - a)(c + a) = 0

Then, (a²-b²)+(b²-c²)+(c²-a²)

= a²-b²+b²-c²+c²-a² =0

so ,prove that..