Question

(a+b)(a-b) (b-c) (b+c)(c-a) (c+a)=0​

Answer 1

Step-by-step explanation:

I think it is correct friend

Answer 2

Answer:

Step-by-step explanation:

Using Identity = (a + b)(a - b) = a² - b²

(a+b)(a-b) (b-c) (b+c)(c-a) (c+a)=0​ ⇒

a² - b² + (b² - c²) + (c² - a²) = 0

a² - a² - b² + b² + c² - c² = 0

0 = 0

Hence, Proved.