Question

(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0​

Answer 1

Answer:

57

Step-by-step explanation:

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Answer 2

Answer:

Answer

(a−b)(a+b)+(b−c)(b+c)+(c−a)(c+a)=0

LHS=a

2

−b

2

−ab+ab+b

2

−c

2

+bc−bc+c

2

−a

2

−ac+ac

we see the terms cancel each other hence equation reduced to zero

Or we can also use identity (a−b)(a+b)=a

2

−b

2

to find similar result.