Question

(a-b)(a+b)+(b-c) (b+c)+(c-a) (c+a)=0

Answer 1

Hi Friend !!!

Here is ur answer !!!

(a-b)(a+b) + (b-c)(b+c) + (c-a) (c+a)

= a²-b²+b²-c²+c²-a²

= 0


Hope it helps u :-)

Answer 2

Ahoy,

(a-b)(a+b) +(b-c)(b+c) + (c-a)(c+a)

=> $({a}^{2} - {b}^{2}) +( {b}^{2} - {c}^{2} ) + ({c}^{2} - {a}^{2})$

=>a^2-b^2+b^2-c^2+ c^2- a^2

=> 0. (because the signs are opposite)

Cheers!