Question

(a-b)(a+b)+(b+c)(b+c)+(c-a)(c+a)​

Answer 1

Hey mate, here is your answer -:)

♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤

$= (a - b)(a + b) + (b + c)(b + c) + (c - a)(c - a) \\ = {a}^{2} + ab - ab - {b}^{2} + {b}^{2} + bc + bc + {c}^{2} + {c}^{2} - ac - ac + {a}^{2} \\ = {2a}^{2} + 2bc + {2c}^{2} - 2ac$

♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤♤

HOPE it helps to you!!!

Answer 2

Answer:

a^2 - b^2 + b^2 + c^2 + 2bc + a^2 - c^2

=> 2a^2 + 2bc