Math, asked by harshubhat6486, 10 hours ago

[a-b][a+b]+[b-c][b+c]+[c-a][c+a]

Answers

Answered by monalishamurmu12

0

Answer:

[a-b][a+b]+[b-c][b+c]+[c-a][c+a]

=[a²-b²]+[ b²-c²] + [c²-a²]

=[a²-b²+b²-c²+c²-a²]

=0

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