Math, asked by biswanathdey462, 1 month ago

(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a)
please help me​

Answers

Answered by NewtonofINDIA
0

= a²-b²+b²-c²+c²-a² = 0

pls mark as brainliest

Answered by roshni8415
0

Answer:

1

a  {}^{2}  - b {}^{2}  + b {}^{2}  - c {}^{2}  + c {}^{2}  - a {}^{2}

so = 1

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