Question

(a+b)(a-b)+((b+c)(b-c)+(c+a)(c-a) simplify​

Answer 1

Answer:

a²-b²+b²-c²+c²-a²=0(by cancellation) mark me as the brainliest

Answer 2

Answer:

(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a),

=(a²-b²)+(b²-c²)+(c²-a²),

=(a²-b²+b²-c²+c²-a²),

In this case, each variable cancels it's negative version.

= 0

NOW, THAT'S THE CORRECT ANSWER.