Question

(a - b)(a + b)+(b-c)(b + c)+(c -a) (e+a) - 0​

Answer 1

Step-by-step explanation:

(a-b) (a+b)+(b-c) (b+c)+(c-a) (c+a)-0

$= ( {a}^{2} - {b}^{2} ) + ( {b}^{2} - {c}^{2} ) + ( {c}^{2} - {a}^{2} ) - 0$

$= {a}^{2} - {b}^{2} + {b}^{2} - {c}^{2} + {c}^{2} - {a}^{2} - 0$

$= 0 - 0$

$= 0$

Answer 2

Step-by-step explanation:

(a-b)(a+b) = a^2-b^2 _______ (1)

(b+c)(b-c) = b^2-c^2________(2)

(c+a)(c-a) = c^2-a^2________(3)

(1)+(2)+(3) = 0