Question

a×b+a×c = ?

please give answer​

Answer 1

Please Read

Though this might not be the answer you're looking for, but if you are a student I hope you read my answer.

Concept

• Factorization
• Expanding

Before we start

Let's see why we learn expanding before factorization.

Factorization is the method of showing the sum as multiplication.

Expanding is the method of showing the multiplication as the sum.

Now we see both are the reverse of each other.

Technique

Now as we see in the expanding

$\sf{a(b+c)=ab+ac}$

To reverse this, we need to know what is multiplied to the bracket.

$\sf{ab+ac=a\times b+a\times c}$

As we see here, there is a common factor.

To factorize this, we divide all then put in the bracket.

$\sf{a(\dfrac{\cancel{a}b}{\cancel{a}} +\dfrac{\cancel{a}c}{\cancel{a}} )=a(b+c)}$

Answer

$\sf{a(b+c)}$

Answer 2

Though this might not be the answer you're looking for, but if you are a student I hope you read my answer.

Concept

Factorization

Expanding

Before we start

Let's see why we learn expanding before factorization.

Factorization is the method of showing the sum as multiplication.

Expanding is the method of showing the multiplication as the sum.

Now we see both are the reverse of each other.

Technique

Now as we see in the expanding

\sf{a(b+c)=ab+ac}a(b+c)=ab+ac

To reverse this, we need to know what is multiplied to the bracket.

\sf{ab+ac=a\times b+a\times c}ab+ac=a×b+a×c

As we see here, there is a common factor.

To factorize this, we divide all then put in the bracket.

\sf{a(\dfrac{\cancel{a}b}{\cancel{a}} +\dfrac{\cancel{a}c}{\cancel{a}} )=a(b+c)}a(

a

a

b

+

a

a

c

)=a(b+c)

Answer

\sf{a(b+c)}a(b+c)