Question

(A-B)=A <=>A intersection of set B =pie .​

Answer 1

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${A-B}$ means everything in A except for anything in${A∩B}$

$A-B=A∩{B}^{c}$(A intersect B complement)

pick an element x

${let x∈(A-B)}$

$Therefore\:{x∈A\:but\:x∉B}$

${x∉B\:means\:x∈}{B}^{c}$

$x∈A and x∈{B}^{c}$

$x∈(A∩{B}^{c})$

$Therefore\:A-B=A∩{B}^{c}$

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Answer 2

Step-by-step explanation:

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