Question

(a?+b): (a2-b-) =(ac+bd): (ac-bd)​

Answer 1

ANSWER

(a2+b2)x2−2(ac+bd)x+(c2+d2)=0 has equal roots.

Therefore, discriminant =0

Thus [2(ac+bd)]2+4(a2+b2)(c2+d2)

⇒a2c2+b2d2+2ac.bd=a2c2+a2d2+b2c2+b2d2

⇒(ad−bc)2=0$

⇒ad−bc=0

⇒ad=bc