(a + b)(a² - b²)=
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Answer:
Step-by-step explanation
A1=ab
A2=b²
A3=a (a-b) = a²-ab
A4=b (a-b) = ab-b²
Sixthly, Refer step 5, remove an above rectangle and a square which has areas as A1 and A2, after removing this, we have one rectangle and a square which have areas as A3, A4. For proving this formula, it is required to find out combined area of a rectangle (A3) and a square (A4), here, combined area can be called as A,
Hence,
A=A3+A4 ——————— (1)
A= (a + b) (a – b) ———— (2)
A3=a (a-b) = a²-ab ———- (3)
A4=b (a-b) = ab-b² ———- (4)
Balance the above areas,
A=A3+A4
(a + b) (a – b) = a²-ab + ab-b²
Cancel ‘ab’ from right hand side.
(a + b) (a – b) = a²– b²
Hence, it is proved.
Proof of (a + b) (a – b) = a²– b² by Numerical method:
For instance, if we take a= 4m and b=2m,
Hence,
a²– b²=(a + b) (a – b)
(4²-2²)=(4+2) (4-2)
16-4 = 6 X 2
12=12
LHS = RHS
Thus, it is proved.