( a + b ) ( a³ - b³ ) ÷ a² - b² =
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Answer:
We know two formulas, that is:
a³-b³= (a-b)(a²+b²+ab)
a²-b²= (a+b)(a-b)
So putting the evaluations of the formulas in the given one.
(a³-b³)/(a²-b²)
= (a-b)(a²+b²+ab)/(a+b)(a-b)
= (a²+b²+ab)/(a+b)
We know
(a+b)²=a²+b²+2ab
a²+b²=(a+b)²-2ab
So,
= {[(a+b)²-2ab]+ab}/(a+b)
{(a+b)²-2ab+ab}/(a+b)
{(a+b)²-ab}/(a+b)
(a+b)²/(a+b) - ab/(a+b)
(a+b) - ab/(a+b)
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