A, B & C form a triangle where ∠ BAC = 90°. AB = 14.9 mm and BC = 19.2 mm. Find the length of AC, giving your answer rounded to 1 DP.
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Answer:
since angle A=90 deg
so it is a right angled triangle
Let AC be the base of the triangle then
AB is the perpendicular of the triangle.
AB=14.9 mm
BC=19.2 mm
Using Pythagoras Theorem,
Hypotenuse^2 = Base^2 + Perpendicular^2
19.2^2 = Base^2 + 14.9^2
19.2^2-14.9^2=Base^2
(19.2-14.9) (19.2+14.9)=Base^2 ∴ a+b) ( a-b) = (a^2-b^2
4.3 × 34.1 = Base^2
146.63 =Base^2
√146.63 = Base
12.11 mm≈ =Base
Therefore,
AC=12.11 mm
Step-by-step explanation:
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