Question

A, B & C form a triangle where
∠
BAC = 90°.
AB = 7.9 mm and CA = 6.7 mm.
Find the length of BC, giving your answer rounded to 1 DP.

Answer 1

Step-by-step explanation:

In triangle ABC

ANGLE BAC=90°

Using Pythagoras theorem

(Hypotenuse)^2 = (side)^2 + (side)^2

BC^2 = AB^2+BC^2

= 7.9^2+ 6.7^2

= 107.3

BC = 10.35

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Answer 2

Let

∆Abc is a right angle triangle because BAC=90°

distance of AB=7.9mm

distance of CA=6.7mm

Distance of BC=?

Bc^=CA^+AB^

BC^=7.9^+6.7^

Bc^=62.41+44.89

BC^=107.3

BC=√107.3

BC=10.35

Distance of BC=10.35mm

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