A, B & C form a triangle where ∠
BAC = 90°.
AB = 9.8 mm and BC = 20.9 mm.
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ABC is a triangle.
Given: AB = 9.8 mm and BC = 20.9 mm.
A/Q,
by Pythagoras theorem,
BC² = AB² + AC²
→ 20.9 ² = 9.8² + AC²
→ AC² = 20.9² + 9.8²
→ AC² = 436.81 + 96.04
→ AC² = 532.85
→ AC² = 23.08² (approximately)
→ AC = 23.08.
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