a
B. An object is thrown in vertically
up ward direction with a velocity of
10 m/s. calculate
maximum height attained
by the object. Also
find the
time taken to reach?
(take a=10m/s^2).
Answers
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Answer:
time is 1sec and height 15m
Explanation:
u=10
h=?
v=0
t=?
a=10
according to first equation of motion
v=u+at
0=10+10t
-10=10t
t=-1 or t=1
according to second equation of motion
s=ut+½at²
s=10+½×10×1²
s=10+5
s=15
therefore time is 1 second and height is 15m
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