A,B and a can do a piece of work in 6, 8 and 12 hours respectively they started the work together and after one hour we left the work .in how much time will the remaining work be completed by A and C?
Answers
Answer:
A do his work in 6 hours
C do his work in 12 hours
B do his work in 8 hours
total time to do the work is 6+12+8 = 26 hours
A and C need to complete the work 26/2=13 hours.
Answer:
A and C will complete the remaining work in 4 hours.
Step-by-step explanation:
Time taken by A to do the piece of work = 6 hours
Rate at which A can the piece of work / efficiency of A =
Time taken by B to do the piece of work = 8 hours
Rate at which B can the piece of work / efficiency of B =
Time taken by C to do the piece of work = 12 hours
Rate at which C can the piece of work / efficiency of C =
A, B and C worked together for 1 hour.
∴ Amount of work done = Rate at which the work done * Time taken
Since 3 people worked together, the combined rate at which the work done / combined efficiency =sum of their efficiencies.
So the amount of work they completed in that hour =
=
=
=
i.e., of the work was completed when they worked for 1 hour.
--------------------------------------------------------------------------------------------------------------
B left after 1 hour.
Amount of work left to do = 1 -
=
Now, of the work has to be completed by A and C alone.
Combined efficiency of A and C = +
=
=
=
Now the time taken for them to complete the work = 1 ÷ their combined efficiency
= = 4
∴ The time taken for A and C to complete the remaining work is 4 hours.
Special Thanks to a Brainly Expert @navanithishere.