Question

a,b and c alone can do a piece of work in 10 days ,15 days and 12 days respectively. They together started the work but after 3 days ,A and b both left . In how many days, c alone will complete the remaining work? ​

Answer 1

Answer:

3

Step-by-step explanation:

T.W = LcM(10,15,12)= 60 units

their efficiency,

A => 60/10 = 6 units/day

B => 60/15 = 4 units/day

C => 60/12 = 5 units/day

their 3 days work(together)

= 3 × (6+4+5) = 45 units

remaining work = 15 units

C alone will complete remaining work in=15/5 = 3 days