Question

a,b and c are non 0. a+b+c=0.show that a²/bc + b²/ca+ c²/ab = 3
         x= p+2q the whole root +p-2q the whole root
             p+2q the whole root -p-2q the whole root         - show that qx²-px+q=0

Answer 1

a³ + b³ + c³ - 3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)
a³ + b³ + c³ - 3abc = 0 x (a²+b²+c²-ab-bc-ca) = 0
Hence a³ + b³ + c³ = 3abc
Dividing both sides by abc,

(a³/abc) + (b³/abc) +  (c³/abc) = 3

a²/bc  + b²/ca  + c²/ab = 3
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Please re-write the second question using brackets for terms separated by + or - signs. Second half of question is not clear.
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