A, b and c are non zero numbers and 1+a^3/a=1+b^3/b=1+c^3/c then what is the value of a^3+b^3+c^3
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I'm done short method
I hope you help !!
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We know, a^3 + b^3 = (a+b)^3 - 3ab(a+b)
Therefore, x^3 + 1/x^3 = (x + 1/x)^3 -3.x.1/x (x+1/x)
= (root 2)^3 -3 * root 2
= 2 root2 - 3 root2
= - root 2 is the answer
I hope you help !!
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We know, a^3 + b^3 = (a+b)^3 - 3ab(a+b)
Therefore, x^3 + 1/x^3 = (x + 1/x)^3 -3.x.1/x (x+1/x)
= (root 2)^3 -3 * root 2
= 2 root2 - 3 root2
= - root 2 is the answer
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