Question

A, B and C are points on a circle.
DE is a tangent to the circle at C.
Angle BAC = 19° and angle ACB = 93º.
Find the value of x. Give reason
X=

Answer 1

Answer:

the reason is idk what's the answer

Answer 2

Given :- A, B and C are points on a circle. DE is a tangent to the circle at C. Angle BAC = 19° and angle ACB = 93º.

To Find :- x = ?

Solution :-

In ∆ABC we have,

→ ∠BAC = 19°

→ ∠ACB = 93°

So,

→ ∠BAC + ∠ACB + ∠ABC = 180° { By angle sum property. }

then,

→ 19° + 93° + ∠ABC = 180°

→ 112° + ∠ABC = 180°

→ ∠ABC = 180° - 112°

→ ∠ABC = 68°

therefore,

→ ∠x = ∠ABC { Alternate segment theorem }

→ ∠x = 68° (Ans.)

Hence, the value of x is equal to 68° .

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