A, B and C are the three elements belonging to third period of the periodic table. (symbols are not real)
• The element belongs to 18 th group.
* When element B reacts with element A. B donates electrons to A.
a) Name the family to which C' belongs ?
b) Which element is metallic in nature?
c) Write down the given elements in the order as present in the periodic table.
Answers
Answer:
(a) A belongs to group 17. There are 7 electrons in its valance shell. Therefore it tend to accept one electron to complete octet. Hence, it is a non-metal.
(b) C is less reactive than A. As both elements belong to same group and going down to group size of element increases. A is a smaller than C therefore the cloud of electron density surrounding the nucleus is more compact. The stability of completing the octet for A is greater than for C as A is more keen to obtain an electron than C.
(c) C is smaller than B. C and B belongs to same period. Atomic radius decreases from left to right within a period. This is caused by the increase in the number of protons and electrons across a period. One proton has a greater effect than one electron; thus, electrons are pulled towards the nucleus, resulting in a smaller radius.
(d) A will form anion A
−
. A belongs to group 17. There are 7 electrons in its valance shell. Therefore it tend to accept one electron to complete octet and forms anion.
Explanation:
hope this will help u
Answer:
a) C belongs to noble gas families
b) B metalic in nature since it donates electron
c) order of presence is B, A, C