A, B and C are three persons to cover 300 km displacement in such a way that two of them can ride a bike at a maximum speed of 60km/hr and one has to walk at a maximum speed of 15 km/hr. What will be the minimum time required for all of them to reach their destination?
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For A and B
Distance = 300 km
Speed = 60 km/hr
T= ?
T1 = distance / speed
T= 300/60 h
T1 = 5 hours
For C
Distance = 300 km
Speed max = 15 km/hr
Time = distance/ speed
T= 300/15 h
T2 =20 hr
Since we have to find the minimum time required for all of them to reach their destination means when everyone will be present at the finish line what will be the total time taken, therefore we will take the HCF (highest common factor) of T1 and T2
Of 5 and 20 hours
The hcf of 5 and 20 is 20 hours.
Therefore minimum time required for all of them to reach their destination is 20 hours.
Distance = 300 km
Speed = 60 km/hr
T= ?
T1 = distance / speed
T= 300/60 h
T1 = 5 hours
For C
Distance = 300 km
Speed max = 15 km/hr
Time = distance/ speed
T= 300/15 h
T2 =20 hr
Since we have to find the minimum time required for all of them to reach their destination means when everyone will be present at the finish line what will be the total time taken, therefore we will take the HCF (highest common factor) of T1 and T2
Of 5 and 20 hours
The hcf of 5 and 20 is 20 hours.
Therefore minimum time required for all of them to reach their destination is 20 hours.
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