A, B and C are three pipes connected to a tank. A and B together fill the tank in 6 hrs. B and C together fill the tank in 10 hrs. A and C together
fill the tank in 15/2 hrs. In how much time will A, B and C fill the tank separately?
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Answer:
Part time in 2 hours=62=31
Remaining part=(1−31)=32.
∴(A+B)'s 7 hour's work=32
(A+B)'s 1 hour's work=212
∴ C's hour's work={(A+B+C)'s 1 hour's work}−{(A+B)'s 1 hour's work}
=(61−212)=141
∴ C alone can fill the tank in 14 hours.
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does the question you written is 100%correct
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