A, B, and C are three points on a circle. AB = AC =7√2 cm and ㄥBAC = 90, then the radius is equal to?
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Step-by-step explanation:
From the figure we know that
∠AOB+∠AOC+∠BOC=360
o
By substituting the values
90
o
+110
o
+∠BOC=360
o
On further calculation
∠BOC=360
o
−90
o
−110
o
By subtraction
∠BOC=360
o
−200
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∠BOC=160
o
So we get
We know that
∠BOC=2×∠BAC
It is given that ∠BOC=160
o
∠BAC=
2
160
o
By division
∠BAC=80
o
Therefore, ∠BAC=80
o
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