Question

A,B and C are three points on a circle with centre O. if angle AOB = 120 then find angle AOC
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Answer 1

Step-by-step explanation:

From the figure we know that ∠AOB + ∠AOC + ∠BOC = 360o By substituting the values 90o + 110o + ∠BOC = 360o On further calculation ∠BOC = 360o – 90o – 110o By subtraction ∠BOC = 360o – 200o So we get ∠BOC = 160o We know that ∠BOC = 2 × ∠BAC It is given that ∠BOC = 160o ∠BAC = 160o/2 By division ∠BAC = 80o Therefore, ∠BAC = 80o.Read more on Sarthaks.com - https://www.sarthaks.com/727708/figure-and-are-three-points-the-circle-with-centre-such-that-aob-90and-aoc-110-find-bac