Question

A,B and C are three points on level ground.Given that the bearing of B from A is 122 degree,CAB is 32 degree and ABC is 86 degree, calculate the bearing of C From B. In CAB The angle is at A and in angle ABC the angle is at B.​

Answer 1

The bearing of C from B is 28°.

Step-by-step explanation:

See the attached diagram.

If N denotes the North direction then ∠ BAN = 122° (Given).

Now, in triangle Δ ABC, ∠ CAB = 32° and ∠ ABC = 86° (Given)

Here, from point B if we draw a line parallel to AN as BN', then

∠ N'BB' = 122°

So, ∠ ABN' = 180° - 122° = 58°

Then, ∠ CBN' = ∠ ABC - ∠ ABN' = 86° - 58° = 28°

Therefore, the bearing of C from B is 28°. (Answer)