Question

a,b and c are three rational number. Explain why the results of a(b-c) is different from a(c-b)? Given (a not equal to 0 and b not equal to c)​

Answer 1

Answer:

a(b-c) is different from a(c-b)

Let LHS = a(b-c)

And RHS = a(c-b)

Then, Is a(b-c) = a(c-b) ?

ab - ac = ac - ab

-ac+ab = ac-ab

Hence proved a(b-c) is not equal to a(c-b)

For example ->

let a = 2, b = 3, c = 4

then according to a(b-c) = a(c-b) equation

->2(3-4) = 2(4-3)

->2(-1) = 2(1)

-> -2 = 2

LHS is not equal to RHS