a , b and c are three vectors such that c is perpendicular to both a and b What is the value of a cross b cross c?
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a × b × c = 0
Step-by-step explanation:
Given that,
• c and a are perpendicular to each other,
then c . a = 0
• c and b are perpendicular to each other,
then c . b = 0
Now, a × b × c
= (a × b) × c
= - c × (a × b)
= - {(c . b)a - (c . a)b}
= - {(0)a - (0)b}
= 0
Rules:
• a × (b × c) = (a . c)b - (a . b)c
• b × (c × a) = (b . a)c - (b . c)a
• c × (a × b) = (c . b)a - (c . a)b
• a . b = b . a, since (.) is commutative
• a × b = - b × a, since (×) is not commutative
Homework:
Let a = - 3i + 7j + 5k, b = - 5i + 7j - 3k, c = 7i - 5j - 3k. Find a × (b × c) in terms of i, j, k and then verify a × (b × c) = (a . c)b - (a . b)c.
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