A b and c are +ve integers and f(x) =ax^2+bx+c=0 has distinct roots in(0,1)
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we have to find value of a , b , c
since 0 and 1 is a factor of f(x)
then -. (x-0) and (X-1) is a factor of f(x)
therefore f(x) = (x-0)(x-1)
f(x) = x^2 - x
comparing _ ax^2 + bx + c and x^2 - x
a = 1 , b = -1 , c = 0
since 0 and 1 is a factor of f(x)
then -. (x-0) and (X-1) is a factor of f(x)
therefore f(x) = (x-0)(x-1)
f(x) = x^2 - x
comparing _ ax^2 + bx + c and x^2 - x
a = 1 , b = -1 , c = 0
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