Question

A b and c are +ve integers and f(x) =ax^2+bx+c=0 has distinct roots in(0,1)

Answer 1

we have to find value of a , b , c

since 0 and 1 is a factor of f(x)

then -. (x-0) and (X-1) is a factor of f(x)

therefore f(x) = (x-0)(x-1)

f(x) = x^2 - x

comparing _ ax^2 + bx + c and x^2 - x

a = 1 , b = -1 , c = 0