A,B and C can complete a job alone in 10,12 and 15 days respectively. How long will they take to finish the job if they work together?
Answers
Answer:
Let the work be completed in x days.
A's 1 days' work =
10
1
⇒A's (x−5) days' work =
10
(x−5)
B's 1 days' work =
12
1
⇒B's (x−3) days' work =
12
(x−3)
C's 1 days' work =
15
1
⇒C's x days' work =
15
x
⇒
10
x−5
+
12
x−3
+
15
x
=1
⇒
60
6(x−5)+5(x−3)+4x
=1
⇒6x−30+5x−15+4x=60
⇒15x=60+45=105⇒x=7
∴ The work was completed in 7 days.
Answer:
Well let’s see how much work they can do in 1 day
A can do 1/12 of that
B can do 1/15
and C can do 1/10
So all of them working together in one day they will manage to finish
112+115+110=
560+460+660=
1560=14
So if they work all together they will do 1/4 th of the work in one day
Therefore they will need 4 days to finish it all !
Another way to go is to think that in 60 days A will finish the job 5 times, B 4 times and C 6 times.
So all of them combined together will get the job finished 15 times in 60 days therefore they need 4 days for finishing the work once
Step-by-step explanation:
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