a b and c can complete a piece of work in 15 20 and 30 days respectively. all three of them started working together and after two days a quit. b left six days before the completion of the work. in how many days was the work completed
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total work=lcm of 15,20,30=300
a 1 day work=300/15=20
b 1 day work=300/20=15
c 1 day work=300/30=10
(a+b+c) 1 day work=20+15+10=45 days
let x be the days to complete the work
then a working days =2
b working days=x-6
c working days=x
now 20x+15(x-6)+10x=300
20×2+15x-90+10x=300
25x-50=300
x=350/25=14 days
a 1 day work=300/15=20
b 1 day work=300/20=15
c 1 day work=300/30=10
(a+b+c) 1 day work=20+15+10=45 days
let x be the days to complete the work
then a working days =2
b working days=x-6
c working days=x
now 20x+15(x-6)+10x=300
20×2+15x-90+10x=300
25x-50=300
x=350/25=14 days
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