A, B and c can complete a work 10,12,15 days respectively. they Start the work together but a left the work before 5days to the complete of work b also left the work 2days after a. in how many days the total work will complete.
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4 days.
A, B and C can do the work in 12, 15 & 20 days respectively. They are essentially doing the same work, regardless of what the work is actually. Let the amount of work they do, in total, be x. This will be equal for all of them. For calculation, assume this to be the LCM of all, so that we don't have to deal with fractions.
Now, LCM of 12, 15 & 20 is 60. Dividing 60 by respective days will give us efficiency of A,B & C. Which is
A can do 5 unit of work in a day.B can do 4 unit of work in a day.C can do 3 unit of work in a day.
All of them work for two days, 2 x (5+4+3) = 24 unit of work. Remaining work to do is 60–24 = 36. Now, C lefts and remaining work is done by b and c. They will take, 36/(5+4) = 4 days.
Peace !!
A, B and C can do the work in 12, 15 & 20 days respectively. They are essentially doing the same work, regardless of what the work is actually. Let the amount of work they do, in total, be x. This will be equal for all of them. For calculation, assume this to be the LCM of all, so that we don't have to deal with fractions.
Now, LCM of 12, 15 & 20 is 60. Dividing 60 by respective days will give us efficiency of A,B & C. Which is
A can do 5 unit of work in a day.B can do 4 unit of work in a day.C can do 3 unit of work in a day.
All of them work for two days, 2 x (5+4+3) = 24 unit of work. Remaining work to do is 60–24 = 36. Now, C lefts and remaining work is done by b and c. They will take, 36/(5+4) = 4 days.
Peace !!
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